A box of 20 kg mass is pulled by force F with constant velocity on a horizontal surface. If force of friction is 49 N, work done during displacement of 10 m is (A) 490 (B) 245
(c) 980 (D) zero
GSEB - Class 9 Chapter - 1. Work, Energy and Power Page 9
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at constant velocity F=0so work=0
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frictional force is opposite to applied force
f= 49 N
s= 10 m
w= 49*10= 490 J/S
f= 49 N
s= 10 m
w= 49*10= 490 J/S
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