Question

A box of 5kg is placed kn a horizontal surface and pullwd with 10 n force from lwft and 15 n force from right .Ghe net force

Answer 1

F=mxa. m is mass in kg, a is acceleration in m/s2. F is force in Newton.

So 5x2=10N

Answer 2

Given:

mass = 5Kg

Forces acting = 10 N and 15 N

To Find:

net force acting

Solution:

Here,

F1 = force acting on the box from left = 10N

F2 = force acting on the box from right = 15N

now,

F = resultant force

let us suppose the right direction as positive direction

F = - F1 + F2

F = -10 + 15

F = 5N in right direction.

So, net force F = 5N.