Question

A box of 600 bulb contain 12 defective bulb.One bulb is taken out . At rendom from this box. Then the probability that it's is non defective bulb is

a) 143/150
b) 147/150
c) 1/25
d) 1/59

please solve fast
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Answer 1

Answer:

Total number of bulbs = 600

Total number of non-defective bulb = 600-12=588

P (non-defective bulbs) = 588/600

=0.98

Step-by-step explanation:

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Answer 2

$\huge \bf \underline{Answer}$

$\bf{ \boxed{ \underline{ \red{ \tt{\dfrac{49}{50 \: }}}}}}$

_____________________________________

$\sf \huge \underline \red {Given}$

A box of 600 bulb contain 12 defective bulb.One bulb is taken out . At random from this box

_____________________________________

$\sf \underline{step \: by \: step \: explanation}$

• The number of bulb in the box = 600

• The number of defective bulb in box = 12

___________________________________

$\sf \underline{according \: to \: question}$

• A is getting of defective bulb

$\rm \implies \red{n(A) = 600}$

• B is getting of non defective bulb

$\rm \implies \red{n( \:B ) = 12}$

__________________________________

$\tt \implies \pink{p(E) = n(A) - n(B)}$

$\tt \implies \orange{ = 600 - 12 = 588}$

Now,

$\tt \implies \pink{p(E) = \dfrac{n(A)}{n(B)}}$

$\tt \implies \red{ \dfrac{588}{600}}$

$\tt \implies \pink{ = \dfrac{49}{50}}$

i hope it's help uh