Question

A box of 600 bulbs contains 12 defective bulbs. One bulb is taken out at random from this box. Then the probability that it is non-defective bulb is: *

Answer 1

Answer:

P (non-defective bulb) = 1 – P (Defective bulb)

= 1 – (12/600)

= (600 – 12)/600

= 588/600

= 147/150

hope it helps

Answer 2

Answer:

mark the above⬆ one as brainliest