Question

A box of 600 bulbs contains 12 defective . one bulb is taken out of box. What is the probability that it is a non defective bulb?​

Answer 1

Total number of bulbs = 600

Total number of non-defective bulb = 600-12=588

P (non-defective bulbs) =

600

588

=0.98

Answer 2

The probability that one bulb taken out random is non-defective is \dfrac{49}{50}

50

49

.

Step-by-step explanation:

Given as :

The number of bulb in the box = 600

The number of defective bulb in box = 12

Let The probability that one bulb taken out random is non-defective = p(E)

According to question

As out of 600 bulbs, 12 bulbs are defective

So, The number of non-defective bulb = 600 - 12 = 588

Now, out of 600 bulbs, 1 bulb is chosen in {C_{1}}^{600}C

1

600

And favourable case of chosen non-defective = {C_{1}}^{588}C

1

588

So, probability = \frac{{C_{1}}^{588}}{{C_{1}}^{600}}

C

1

600

C

1

588

Or, p(E) = \dfrac{588}{600}

600

588

Or, p(E) = \dfrac{49}{50}

50

49

Hence, The probability that one bulb taken out random is non-defective is \dfrac{49}{50}

50

49

. Answer