A box of 600 electric bulbs contain 12 defective bulbs one bulbs os taken out at random from this box what is the world probability that is a non defective bulb
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1
A box contain bulb=600
Defective bulb=12
Not defective bulb=600-12=588
P(not defective bulb)=588/600
=49/50
Akhilpathania:
hlo
Answered by
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Total no of outcomes =600
Probability of getting non defective bulb =
600-12
=588
Probability of getting non defective bulb =no of favourable outcomes / Total no of outcomes =588 / 600 = 49 / 50
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