Question

a box of 600 electric bulbs contains 12 defective bulb 1 bar is taken out at random from this what is the probability that is non defective bulb​

Answer 1

591/600...is the probablity

Answer 2

P(E) =non defective bulbs

P(not E) = defective bulbs

Now according to the formula

P(E) +P(not E) =1

Soo here 12 are defective bulbs soo P(not E) =12/600 =0.02

Now put in formula

P(E) +0.02=1

P(E) =1-0.02

P(E) =0.98

Here is ur answer

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