A box of 600 electric bulbs contains 12 defective bulb. One bulb is taken out at random from this box. What is the probability that it is a non-defective bulb?
(ANS:- 49/50)
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to get no. of bulbs not defective /total no of bulbs-defective ones=600-12=588
prob. of nondefective bulb
=no. of non defective /total no. of bulbs
=588/600. (division by 12 of 588 and 600 )
=49/50
prob. of nondefective bulb
=no. of non defective /total no. of bulbs
=588/600. (division by 12 of 588 and 600 )
=49/50
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