A box of 600 electric bulbs contains 12 defective bulbs one bulb is taken Out at random from thisis box what is the probability that it is a non defective bulb ?
Answers
Answered by
3
Answer:
0.98
Step-by-step explanation:
total = 600
defective = 12
non defective = 600-12 = 588
P(non defective )= 588 / 600 = 0.98
Answered by
0
Answer:
49/50
Explanation:-first of all we will find how many of them are non defective
i.e, 600-12=588
therefore, the probability of getting a non defective bulb is =>588/600
=>147/150
=>49/50
Hope It Helps....
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