Math, asked by alishashirodkar23, 10 months ago

A box of 600 electric bulbs contains 12 defective bulbs one bulb is taken Out at random from thisis box what is the probability that it is a non defective bulb ?


Answers

Answered by shavetag12
3

Answer:

0.98

Step-by-step explanation:

total = 600

defective = 12

non defective = 600-12 = 588

P(non defective )= 588 / 600 = 0.98

Answered by preetitiwari0404
0

Answer:

49/50

Explanation:-first of all we will find how many of them are non defective

i.e, 600-12=588

therefore, the probability of getting a non defective bulb is =>588/600

=>147/150

=>49/50

Hope It Helps....

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