A box of candies contains caramel chocolates and chocolates with nuts. There are 3 times more caramel chocolates as there are chocolates with nuts. If there are 20 chocolates total, how many are there of each type?
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Let chocolates with nuts be x
Thus, caramel chocolates would be 3x
Given total chocolates = 20
x + 3x = 20
4x = 20
x = 5
Thus, there are 5 chocolates with nuts
Caramel chocolates = 3 x 5 = 15
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Thus, caramel chocolates would be 3x
Given total chocolates = 20
x + 3x = 20
4x = 20
x = 5
Thus, there are 5 chocolates with nuts
Caramel chocolates = 3 x 5 = 15
Hope it helps :)
Pls mark as brainliest :)
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