Math, asked by inayausmanjt, 22 hours ago

A box of chocolates contains milk, white and dark chocolates in the ratio 5:1:2. The box contains 56 chocolates altogether. How many chocolates in the box are milk, white and dark?

b) 14 of the chocolates have been eaten.
there are 42 chocolates left in the box.
the ratio of the number of milk, white and dark chocolates in the box is changed to 4:1:2

Answers

Answered by hariraj401769
0

Answer:

A) Given : • Total Chocolates = 56 Ratios = 5:1:2 To find : milk chocolates Solution : Denominator = 5 +1+ 2 = 8 Milk Chocolates = 5/8 x 56 = 5 x 56/8 = 280/8 = 35 Therefore, 35 milk chocolates were there in the box.

Answered by limesaga1111
1

Answer:

When the chocolates in the box are 56, the box has 35 milk, 7 white and 14 dark chocolates.

When the chocolates in the box are 42, the box has 24 milk, 6 white and 12 dark chocolates.

Step-by-step explanation:

The box contains milk, white and dark chocolates in the ratio 5:1:2. That means, the milk chocolates in the box are 5x, the white are 1x and the dark chocolates are 2x.

All the chocolates in the box together make 56 of them. So,

5x + 1x + 2x = 56

8x = 56

x = 56/8

x = 7

Now adding the value of x in 5x, 1x and 2x,

5x = 5 × 7 = 35

1x = 1 × 7 = 7

2x = 2 × 7 = 14

Therefore, In the first part, the box contains 35 milk chocolates, 7 white chocolates and 14 dark chocolates.

b) Using the same technique,

The box contains the chocolates in the ratio 4:1:2

That means, 4x milk, 1x white and 2x dark

The total number = 42

4x + 1x + 2x = 42

7x = 42

x = 42/7

x = 6

Adding the value of x in 4x, 1x and 2x;

4x = 4 × 6 = 24

1x = 1 × 6 = 6

2x = 2 × 6 = 12

Therefore, after 14 chocolates are eaten,

24 milk chocolates, 6 white chocolates and 12 dark chocolates will be left.

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