A box of mass 10 kg is kept at rest on a frictionless horizontal surface. It is pushed horizontally with a constant force of 10 N for 10 second. Velocity of the box after 10 second is (n x 10) m/s. What is the value of n?
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Friction force alone is unable to balance mgsin37
0
. Hence, F is required for balancing. Here two cases arise.
Case I:
If the block has tendency to slide down, friction on block will act upwards.
F + 16 = 60
RightarrowF=44N
This is the minimum force required for balancing.
Case II: If the block has on tendency to slide up, friction on block will act downwards.
F = 60 + 16⇒ F= 76 N
This is the maximum force required for balancing.
Therefore, for balancing 44N≤F≤16N
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