A box of mass 2 kg is pushed by horizontal force of 2.5n on a floor. what is the force of friction between the block and floor given that coefficient of static friction is 0.4.
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Hey there,
Normal=Mass*gravity=2*10=20N
μ=0.4
Friction=μN=0.4*20=8 N
Since the force applied is less than static friction so the friction=Force applied.
Therefore friction=2.5 N
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07161020
Ace
Normal=Mass*gravity=2*10=20N
μ=0.4
Friction=μN=0.4*20=8 N
Since the force applied is less than static friction so the friction=Force applied.
Therefore friction=2.5 N
PLEASE MARK AS BRAINLIEST IF HELPFUL!!!
Regards
07161020
Ace
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