Question

A box of mass 25 kg kept on a floor,moving inside just breaking the floor with

acceleration of 0.2 ms-2

.What is the reaction force given by the floor?


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Answer 1

Answer:

Given, m = 30 kg.

Retarding force = -10N

u = 10 m/s

v = 0.

We know, F = ma

-10 = 30 x a

a = -1/3 ms-2

Also, v = u + at

0 = 10 – t/3

Therefore, t = -10 x (-3) = 30 s.

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