A box of mass 3.0 kg slides down a rough vertical wall. The gravitational force on the box is
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Answer:
F= 29.4 N
Explanation:
g= 9.8 m/s²
m= 3.0 Kg
F= m.g = 3 x 9.8 = 29.4 N
If the surface is rough there must be some some frictional force. so the net force will be equal to F- friction. But the question has not asked for the net force so we will stick to our answer.
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