A box of mass 400kg on a carrier of truck that is moving at a spees of 120 km/hr the driver applies brake and slow to speed of 60km/hr in 20sec the constant acceleration generated upon the box in m/sec*
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HIII MATE!!!
GIVEN INFORMATION:-
m=400kg
t=20s
u=120km/h
CHANGING km/h INTO m/s ,we get
=120×1000/3600
=120×5/18
=600/18
=33.3m/s
v=0m/s (because of the breaks applied made the truck stop).
a=v-u/t
=0-33.3/20
=−1.665m/s^2
THANKS
I THINK IT HELPS...
@garu1678
GIVEN INFORMATION:-
m=400kg
t=20s
u=120km/h
CHANGING km/h INTO m/s ,we get
=120×1000/3600
=120×5/18
=600/18
=33.3m/s
v=0m/s (because of the breaks applied made the truck stop).
a=v-u/t
=0-33.3/20
=−1.665m/s^2
THANKS
I THINK IT HELPS...
@garu1678
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