A box of mass 50 g is kept on a horizontal floor. When it is pushed by horizontal force H, is moves with a constant velocity. If it is pushed by horizontal force 1.5 H, it moves with an acceleration of 0.1 meter par second. Find the value of H
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We know that the Newton first law states that the body is be in the position of rest or in uniform motion unless and until an external force is applied to it.
If H is the force applied on it and the body moves with uniform means that the force is equal to zero.
Then,
F = H
U = V
A = 0
M = 50g
If the force of 1.5H applied on it, the body produce an acceleration of 0.1m/s^2
F = 1.5H
A = 0.1m/s^2
M = 50g
So the net force = 1.5H - H
= 0.5H
We know that,
F = ma
0.5H = 50/1000(kg) × 0.1
5/10H = 50/1000 × 1/10
5×1000×10H = 50×1×10
50000H = 500
H = 500/50000
H = 1/100
H = 0.01 Newton
tq
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