Question

A box of mass 60 kg starts from rest at a height li and slides down a slope of length 10 m, which
makes an angle of 25% with the horizontal. It undergoes a constant acceleration of magnitude
2 ms while sliding down the slope.
When the box reaches the bottom of the slope its kinetic energy is:
1. 600J
2 1200 J
3. 2400)
(i) The work done on the box by the gravitational force is:
1. 2500 )
2. 1200
3. 2485 )
​

Answer 1

Answer:

2500

Explanation:

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Answer 2

Answer:

Wb = m*g = 60kg * 9.8N/kg = 588 N. = Wt.

of box.

Fp = 588*sin25 = 248.5 N. = Force

parallel to the slope.

Fp-Fk = m*a

248.5-Fk = 60 * 2 = 120

Fk = 248.5 - 120 = 128.5 N. = Force of

kinetic friction.

Work = Fk * L = 128.5 * 10 = 1285 Joules