A box of mass 6kg is placed on a table. The coefficient of static friction between the box and the table is 0.4. Will the box move if an external horizontal force of 30N is applied on it? ill mark ppl as brainliest etc etc pls solve correctly and pls dont spam
Answers
ok ok I am writing it correctly
In this activity you will solve problems involving friction. You will combine
the model F ≤ μR with Newton’s Second Law and the constant acceleration
equations.
Information sheet The friction model
Friction acts tangentially along surfaces in contact, in the direction that
opposes motion.
Before sliding occurs:
friction is just sufficient to maintain equilibrium and prevent motion.
F < FMAX
On the point of sliding and when sliding occurs:
F = μR
where F is the friction force acting between two surfaces in contact,
μ is the coefficient of friction, and R is the normal contact force.
(Note that sometimes N is used instead of R for the normal contact force.)
You can use the friction model to determine whether a body will slide, what
force will be required to make a body slide, or to find the coefficient of
friction between two surfaces in contact.
Example
A 5 kg box on a horizontal table is pushed by a horizontal force
of 15 N as shown on the right.
If the coefficient of friction is 0.4, will the box move?
Think about
What is the smallest force that could make the box slide along the table?
Solution
The sketch shows the forces acting on the box.
Note that the weight of a box of mass 5 kg is 5g where g = 9.8 ms–2
Since the vertical forces are in equilibrium, R = 5g
Therefore the maximum possible friction is F = μR = 0.4 5g = 19.6 N
The pushing force, 15 N, is less than this and so cannot overcome the
friction.
The box will not move.
I have given the answer so folk me send me thanks