Physics, asked by paridubeyy, 4 months ago

a box of mass 70 kg is lifted up to a certain height h above the ground.if the potential energy of box is 2744 J, tell the height at which the object is with respect to ground?​

Answers

Answered by shashwat2816
2

Answer:

4m

Explanation:

Gravity=9.8m/s^2

Mass=70kg

Height=h.

Potential energy=2744J.

we know that, potential energy=Mass×Gravity×Height

therefore, 2744J=70x9.8×h.

2744J=686×h.

2744/686=h.

4m=h.

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Answered by tarracharan
2

\large{\bold{Aɴsᴡᴇʀ :}}

\:

\sf{\:\:\:●\:Height\:(h)=}\textsf{\textbf{\red{4m}}}

\:

\large{\bold{Gɪᴠᴇɴ :}}

\:

\sf{\:\:\:●\:Mass\:of\:box\:(m) = 70\:kg}

\sf{\:\:\:●\:P.E\:(at\:height\:‘h’) = 2744\:J}

\:

\large{\bold{Tᴏ \:Fɪɴᴅ :}}

\:

\sf{\:\:\:●\:Height\:(h)}

\:

\large{\bold{Fᴏʀᴍᴜʟᴀ\: Usᴇᴅ :}}

\:

\sf{\:\:\:●\:}\boxed{\sf{\color{navy}{P.E = mgh}}}

\:

\large{\bold{Sᴏʟᴜᴛɪᴏɴ :}}

\:

\sf{P.E = mgh}

\sf{2744 = 70\times 9.8\times h}

\sf{h = \dfrac{2744}{686}}

\textsf{\textbf{h = 4m}}

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