A box of mass 70 kg is pulled by a horizontal force of 500 N on the surface of the floor. When the box moves, the coefficient of friction between the floor and the box is 0.50. Calculate the acceleration of box?
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Answer:
a = 2.24m/s^2
Explanation:
mass (m ) = 70 kg
Force (F) = 500N
coefficient of friction (u) = 0.50
Now applying formula ,
f = u R { where f = friction, u = coefficient of friction and R is normal force }
we have to calculate friction therefore
f = 0.50 * mg { R which is normal force always act upwards so equal and opposite force will react downwards which is equal to weight of body = mg therefore we write R = mg }
f = 0.50 * 70 * 9.8
f = 343 N
now we have to calculate a
net force acting on the body
F - f = ma { f is negative because it is opposing the motion }
500 - 343 = 70a
157 = 70a
a = 2.24m/s^ 2
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