Question

A box of mass M is lying on the flat bed of a pickup truck as shown. The truck is moving with a uniform velocity of 15 m/s. What is the value of force of friction between the mass and the bed of the truck?​

Answer 1

Answer:

let the mass of the truck be M then friction force on it is

F=μMg=Ma

a=μg=0.9g

time for truck to come at rest

Vf=Vi+at

0=15−0.9gt

t=35s

friction between crate and truck surface is 

F=mμkg

a=0.7g=7m/s2

so relative acceleration is 9−7=2m/s2

the distance the crate will travel is

S=ut+21at2

S=0+21×2×(35)2

S=2.77m

Answer 2

Answer:

Assuming that mass of truck gt gt mass of crate . Retardation of truck <br>

<br> Retardation of truck <br>

<br> or relative acceleration of ceate <br>

<br> Truck will stop after time <br>

<br> and crate will strike the wall at <br>

<br> As

, crate will come to rest after travelling a distance <br>

<br>

Explanation:

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