Physics, asked by supe1632, 1 year ago

A box of weight 400N is kept on the floor . The area of contact is 4m2 . Find the pressure exerted by box on the floor

Answers

Answered by 472578
22

Answer:

Force=pressure×area

Pressure=force/area

=400/4

=100N/m^2

Explanation: hope you understand ❤️❤️❤️❤️

Answered by VineetaGara
2

Given,

Weight of a box kept on the floor = 400 N

The area of contact of the box = 4m^2

To find,

The pressure exerted by the box on the floor.

Solution,

We can simply solve this numerical problem by using the following method:

Mathematically,

The pressure exerted by a body

= (a total force acting/weight of the body)/(area of contact)

Now, according to the question;

The pressure exerted by the box on the floor

= (a total force acting/weight of the body)/(area of contact)

= (the weight of the body)/(area of contact)

= (400 N)/(4 m^2)

= (400/4) N.m^2

= 100 N.m^2

= 100 Pascals = 100 pa

Hence, the pressure exerted by the box on the floor is equal to 100 Pascals.

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