Question

a box open at the top has a square base of side 80 cm find its height is 1 m 40 cm find the area of metals it required to make the box (ignore the thickness of the seat), and find the cost of metal sheet used at rate of rupees 55 per square metre​

Answer 1

Answer:

Sorry Can't Know..

Step-by-step explanation:

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Answer 2

Given:

Length of the square base $=80$ $cm$

Height of the box $=1$ $m$ $40$ $cm$

To find:

1. The area of the metal.
2. The cost of sheet used for making.

Solution:

We have been given that the box is open and the base of the box to be made is of square shape of side $a=80cm$ . The total height of the box is $1m$ $40cm$.

Step 1

Now,

Since the base is square shape hence, the area of the base will be given by

$A_{1}=a^{2}$    

We have, $a=80cm$ $=0.8m$ , Hence,

$A_{1} =(0.8)^{2}$

$A_{1}=0.64m^{2}$

Now, the lateral surface of the box will have total 4 sides of length (that is the height of the box) as $l=140cm=1.4m$ and  breadth $b=0.8m$ .

Hence, the area of one side of the box is given as

$A_{2}=l$ × $b$

And, for all the 4 sides of the box

$A_{2} =4$ × $l$ × $b$

Substituting the values, we get

$A_{2}=4$ × $1.4$ × $0.8$

$A_{2} =4$ × $1.12$

$A_{2} =4.48$ $m^{2}$

Hence,

The total area of the box = area of the base + lateral surface area

Total area $A=A_{1} +A_{2}$

$A=0.64+4.48$

$A=5.12$ $m^{2}$

Step 2

Now,

We have been given the cost of metal as ₹ $55/m^{2}$

Hence,

The rate of metal for a box of area $5.12$ $m^{2}$ $=55$ × $5.12$

                                                                      = $281.6$ rupees.

Final answer:

Hence, the area of the metal box is 5.12 square meter and the cost of metal sheet for making this box will be ₹ 281.6.