A box open at the top has its outer dimensious 10 cm,9 cm and 2.5 cm and its thickness is 0.5 cm,find the volume of the metal
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Answered by
175
Outer dimensions = L = 10 cm, B = 9 cm and H = 2.5 cm
Outer volume = LBH = 10 × 9 × 2.5 = 225 cu cm
Thickness = 0.5 cm
Inner dimensions =
l = L - 2w = 10 - 2(0.5) = 9 cm
b = B - 2w = 9 - 1 = 8 cm
h = H - w = 2.5 - 0.5 = 2 cm (Open at the top)
Inner volume = lbh = 9 × 8 × 2 = 144 cu cm
Volume of metal = Outer volume - Inner volume
= 225 - 144
= 81 cu cm
Outer volume = LBH = 10 × 9 × 2.5 = 225 cu cm
Thickness = 0.5 cm
Inner dimensions =
l = L - 2w = 10 - 2(0.5) = 9 cm
b = B - 2w = 9 - 1 = 8 cm
h = H - w = 2.5 - 0.5 = 2 cm (Open at the top)
Inner volume = lbh = 9 × 8 × 2 = 144 cu cm
Volume of metal = Outer volume - Inner volume
= 225 - 144
= 81 cu cm
Answered by
38
here is your answer the volume of metal box is 81 cm cube
I will hope this will help you thank you.
I will hope this will help you thank you.
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