A box open at the top has its outer dimensious 10 cm,9 cm and 2.5 cm and its thickness is 0.5 cm,find the volume of the metal
Answers
Answered by
175
Outer dimensions = L = 10 cm, B = 9 cm and H = 2.5 cm
Outer volume = LBH = 10 × 9 × 2.5 = 225 cu cm
Thickness = 0.5 cm
Inner dimensions =
l = L - 2w = 10 - 2(0.5) = 9 cm
b = B - 2w = 9 - 1 = 8 cm
h = H - w = 2.5 - 0.5 = 2 cm (Open at the top)
Inner volume = lbh = 9 × 8 × 2 = 144 cu cm
Volume of metal = Outer volume - Inner volume
= 225 - 144
= 81 cu cm
Outer volume = LBH = 10 × 9 × 2.5 = 225 cu cm
Thickness = 0.5 cm
Inner dimensions =
l = L - 2w = 10 - 2(0.5) = 9 cm
b = B - 2w = 9 - 1 = 8 cm
h = H - w = 2.5 - 0.5 = 2 cm (Open at the top)
Inner volume = lbh = 9 × 8 × 2 = 144 cu cm
Volume of metal = Outer volume - Inner volume
= 225 - 144
= 81 cu cm
Answered by
38
here is your answer the volume of metal box is 81 cm cube
I will hope this will help you thank you.
I will hope this will help you thank you.
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