Question

A box rest in the rear of a truck moving with a deceleration of 2 m/second square. to prevent the box from sliding the approximate value of static coefficient of friction between the box and the bed of truck should be

Answer 1

Hope it helps :) good luck

Answer 2

Answer: 0.2

Explanation: acceleration = -(coefficient of friction)x(acceleration due to gravity)

[ a = -µ*g ]   ---- (1)

a = -2 m/s2

g = 10 m/s2

substituting in (1)

-2 = -µ*10

µ = 2/10

µ = 0.2