Question

A box takes 40 N to start moving when the coefficient of static friction is .54. What is the weight of the box?

Answer 1

oh Bhai maro mujhe maro

Answer 2

Given:

A box takes 40 N to start moving when the coefficient of static friction is 0.54.

To Find:

What is the weight of the box?

Solution:

given , frictional force is , $F=40N$

coefficient of static friction, $\mu_{f}=0.54$

since, we know that

frictional force = static friction coefficient × weight of the box.

therefore, on substituting values, we have

$40=0.54\times W\\\\W= 40/0.54\\\\W=74.08 \ kg$

Hence, weight of the box is 74.08 kg.