Physics, asked by Tohru, 4 months ago

A box that weighs 25 N is pulled by an applied force of 10 N. The coefficient of static
friction between the box and the surface is 0.5. The box will:
(A) Start moving and will continue to increase its velocity
(B) Start moving and maintain a constant velocity
(C) start moving and continue to increase its acceleration
(D) not move​

Answers

Answered by seemabeniwal1980
2

Answer:

option (d) is correct Not move

Answered by hyacinth98
0

The box, on application of a 25N force, will A)start moving and will continue to increase its velocity.

Step-by-step process

Given:
Weight of the box= 25N

Force applied to the box= 10N

Coefficient of static friction;  μ= 0.5

Gravitational acceleration= 9.8 m/sec^2

Calculation:

Fnet= mg- μmg

a=  (1- μ)g

a= (1- 0.5) 9.8

a= 0.5 x 9.8

a= 49.0m/sec^2

Thus, the box, on the application of a force of 25N, will start moving and will continue to increase in its velocity.

Incorrect options

  • b) since the box accelerates at 49.0m/sec^2, it will not move with a constant speed.
  • c) Acceleration will remain constant so this option is incorrect.
  • d)Since there is a constant acceleration, the box will move.

(#SPJ3)

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