Question

A box there is 4 red 3 green and 5 blues ball one ball picked up randomely.what is the probabilit that nither red nor green?

Answer 1

total ball in box is 4+3+5=12
no of balls neither red nor green is-5
then it's probability is 5/12

Answer 2

No of red balls =4
No of green balls =3
No of blue balls= 5
Total no of outcomes = 12

Probablity of red and green balls =
P{E} = 7/12

Therefore probablity of neithr red nor green balls
P{ not E} = 1 - E
= 1 - 7/12 = 5/12
Hence the probablity of neither red nor green is 5/12.