A box was full of balls. 25% of them were red, 2/5 were yellow and the rest were blue. There were 140
blue balls. How many more percent of yellow balls than red balls were there?
pls solve step by step...Answer is 15%
Answers
Step-by-step explanation:
Given:-
A box was full of balls. 25% of them were red, 2/5 were yellow and the rest were blue. There were 140 blue balls.
To find:-
How many more percent of yellow balls than red balls were there?
Solution:-
Let the number of total balls in the box be X
Number of red balls = 25% of total balls
=>25% of X
=>25% × X
=>(25/100)×X
=>(1/4)×X
=>X/4
Number of red balls = X/4
Number of yellow balls = 2/5 of them
=>(2/5)×X
=>2X/5
Number of yellow balls = 2X/5
Remaining balls are blue balls
Number of blue balls =
Total balls -(red balls +yellow balls)
=>X -[(X/4)+(2X/5)]
=>X-[(5X+8X)/20]
=>X-(13X/20)
=>(20X-13X)/20
=>7X/20
Number of blue balls = 7X/20
According to the given problem
Number of blue balls = 140
=>7X/20 = 140
=>7X = 140×20
=>7X = 2800
=>X = 2800/7
=>X = 400
Total number of balls = 400
Number of red balls = X/4
= 400/4
=100
Number of red balls = 100
Number of yellow balls = 2X/5
= 2(400)/5
= 800/5
=160
Number of yellow balls = 160
160>100
Number of Yellow balls > Number of red balls
160-100=60
Number of Yellow balls 60 more than the number of red balls
There are 60 more yellow balls than red balls in the total 400 balls
=>more percent of yellow balls than red balls
(More yellow balls then red balls/Total balls)×100
=>more percentage = (60/400)×100
=>(60×100)/400
=>6000/400
=>60/4
=>15%
Required percentage = 15%
Answer:-
15% more percent of yellow balls than red balls for the given problem