Question

A Box weighing 15N slides down from the top an inclined plane making an angle of 30° with the horizontal. Calculate the Work Done by the force of gravity in moving the box 5.0m along the Plane.

$take \: g = {10ms}^{ - 2} and \: also \: assume \: that \: the \: force \: of \: friction \: is \: negligible$


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Answer 1

Answer:

$work \: = force \times displacement \: \times cos \: theta$

work = 15 N × 5× cos 30

work = 75 × ✓3/2 = (75 × 1.73 )/2

=129.75÷2

=64.875 Joule