Question

A box weighing 20 kg exerts a force of 200 N on the ground. The box covers an area of 2 cm ²on the ground. Find The pressure exerted by the box?

Answer 1

Answer:

Correct option is

C

50 N

Here the required force should be the frictional force.

Thus, F=f=μmg=0.25×20×10=50N

Answer 2

Answer:

Given,

Mass of object = 20 kg

Force Applied = 200 N

Area in contact = 2 cm² = (2 / 10⁶) m²

Formula of Pressure is,

$\frac{(force \: applied)}{(area \: in \: contact)} = \frac{200}{ \frac{2}{ {10}^{6} } } = 100 \times {10}^{6} \\ = 1 \times {10}^{8} pascal$

Hope It Helps:)

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