Question

A box weighing 250 n is kept on the floor. what is the amount of pressure it is exerting on the floor if the length of the box is 50 cm and the width of the box is 25 cm?​

Answer 1

Answer:

Answer is 5 pascal

Explanation:

Because

First we have to find out the are of box

area of rectangle=length×breadth

=50×25

1250

To find out the pressure (pascal)

pascal=Force/Area

P=1250/250

P=5

So the pressure is 5 pascal

Answer 2

Mass of the wooden block, m=5kg

Thrust due to wooden block,

Mg=5kg×9.8$ms^{-2}$

=49N

(a) Surface area of 20cm×10cm surface,

A=(20×10)$cm^{2}$

=(0.2×0.1)$m^{2}$

=0.02$m^{2}$

P= A mg

P=  0.02$m^{2}$

49N  =  0.02

49$Nm^{2}$

 or Pressure, P=2450$Nm^{2}$

(b) Surface area of 40cm×20cm surface,

A=(40×20)$cm^{2}$

=(0.4×0.2)$m^{2}$

=0.08$m^{2}$  

P=  0.08$m^{2}$

49N  =  0.08

49 $Nm^{-2}$

 or Pressure, P=$612.5Nm^{-2}$

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