Question

A box weighing 40N slides down from the top of an inclined plane making an angle of 30°with the horizontal .calculate the work done by the force of gravity in moving the box 2 m long the plane assuming that the force of friction is zero

Answer 1

Answer:

40 JOULE

Explanation:

Resolving the weight of the box along the direction of plane inclined

at an angle of 30° with the horizontal, which is,

F = 40×sin30°

= 40×1/2 = 20N.                  {SIN 30=1/2}

Now the work done in displacing the box on the plane by 2m distance

work done = F× S = 20×2 = 40J.

Answer 2

Answer:

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Explanation:

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