A box weighing 60N slides down from the top of an inclined plane making an angle of 300 with the horizontal if the body slides 4m along the plane, calculate the work done by the force of gravity.
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Answered by
3
Answer:
Given :-
Weight of box = 60 N
Angle = 30⁰
Distance slide = 4 m
To Find :-
Work done
Solution :-
We know that
\bf \: W = Fs cos\thetaW=Fscosθ
Where
F = Force applied
S = Displacement
Cos∅ = Angle made
Since,
The force applied is on the box. So,
We have
F = 60 N
S = 4
Cos∅ = 30
\sf \implies \: 60 \times 4 \times \cos({30}^{ \circ} )⟹60×4×cos(30
∘
)
\sf \implies \: 240 \times \cos( {30}^{ \circ} )⟹240×cos(30
∘
)
We know that
cos30⁰ = √3/2
\sf \implies \: 240 \times \dfrac{ \sqrt{3} }{2}⟹240×
2
3
\sf \implies \: 120 \times \sqrt{3}⟹120×
3
\sf \implies120 \sqrt{3}⟹120
3
So,
Work done is 120√3 Joules
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Answered by
163
αNsωєr :-
GivєN :-
- A box weighing 60 Newton's slides down from the top of an inclined plane making an angle of 300 with the horizontal, the body slides 4m along the plane.
τσ Find:
- The work done by the force of gravity.
Solution:
➾ Work = ️Fs cosθ
➾ Work = 60(4) √3/2
➾ Work = 240 √3/2
➾ Work = 120√3 Joules
✠ Hence, work done = 120√3 Joules.
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