A box weighing 60N slides down from the top of an inclined plane making an angle of 300 with the horizontal if the body slides 4m along the plane, calculate the work done by the force of gravity.
Answers
Given
Weight of the box = 60 N
Angle made by the inclined plane = 30°
Displacement = 4 m
To Find
Work done
Solution
☯ Work = Fs cos θ
Where F is the force applied, s is the displacement & θ is the angle made by the inclined plane
━━━━━━━━━━━━━━━━━━━━━━━━━
✭ According to the Question :
→ Work = Fs cos θ
→ Work = 60 × 4 × cos(30°)
cos(30°) = √3/2
→ Work = 60 × 4 × (√3/2)
→ Work = 240 × √3/2
→ Work = 120 × √3
→ Work = 120√3 J
━━━━━━━━━━━━━━━━━━━━━━━━━
Or we may also use √3 = 1.73
→ Work = 120 × 1.73
→ Work = 207.6 J
∴ The work done on the box is 207.6
Given
Weight of the box = 60 N
Angle made by the inclined plane = 30°
Displacement = 4 m
To Find
Work done
Solution
☯ Work = Fs cos θ
Where F is the force applied, s is the displacement & θ is the angle made by the inclined plane
━━━━━━━━━━━━━━━━━━━━━━━━━
✭ According to the Question :
→ Work = Fs cos θ
→ Work = 60 × 4 × cos(30°)
cos(30°) = √3/2
→ Work = 60 × 4 × (√3/2)
→ Work = 240 × √3/2
→ Work = 120 × √3
→ Work = 120√3 J
━━━━━━━━━━━━━━━━━━━━━━━━━
Or we may also use √3 = 1.73
→ Work = 120 × 1.73
→ Work = 207.6 J
∴ The work done on the box is 207.6