Question

A box which measures 70 cm * 36 cm x 12 cm is to be covered with canvas.
How many metres of canvas of width 80 cm would be required to cover 150
such boxes?​

Answer 1

Answer:

length 70cm

breath 36 cm

height 12 cm

total surface area = 2 ( lb + bh + hl)

= 2 ( 70 × 36 + 36 ×12 + 12 × 70 )

= 2 ( 2520 + 432 + 840 )

= 2 ( 3792)

= 7584cm^2

area of 150 boxes = 7584 × 150

area of canvas = area of 150 boxes

length × width = 7584 × 150

length × 80 = 7584 × 150

length = 7584 × 150 / 80

length = 14420 cm

Answer 2

Answer:

⇰Given that:-

• We have been given that a box measures 70cm × 30 cm × 12cm to be covered by a canvas.

• Let us find total surface area of box using surface area formula of cuboid.

➤Total surface area of cuboid = 2( lb × bh + hl)

⇰Where:-

➠L = Length of cuboid

➠B = Breadth of cuboid

➠W = Weight of cuboid

⇰Then:-

➤Total surface area of box is

⇒2 (70.36 + 36.12 + 12.70)

⇒2 (2520 + 432 + 840)

⇒2 (3792)

⇒7584.

⇰Thus:-

➤The total surface area of box will be

$\bf 7584sq.cm$

⇰Now:-

➤To find the length of canvas that will cover 150 boxes, we will divide total surface area of 150 boxes such by width of canvas as total surface area of canvas will also be the same.

⇰Solution:-

➤Width of canvas × length of canvas = Total surface area of 150 boxes.

➠80cm × length of canvas = 150 × 7584 Sq.cm

$\bf ⇒ \frac{150 \times 7584 {cm}^{2} }{80cm}$

$\bf ⇒\frac{1137600 {cm}^{2} }{80cm}$

$\bf ⇒14220cm$

➤Let us convert the length of canvas into meters by dividing 14220 by 100 as 1 meter equals to 100cm.

➠Length of canvas is

$\bf ⇒ \frac{14220cm}{100 \times \frac{cm}{m} }$

$\bf ⇒ \frac{14220cm}{100} \times \frac{m}{cm}$

$\bf ⇒142.20m$

$\therefore therefore$

⇨142.2 meters of canvas of width 80cm required to cover 150 such boxes.