Question

A box with a weight of 650 Nis lying on the ground and the bottom of the box measures 0.5m by 0.7m. what is the pressure exerted by the box on the ground?​

Answer 1

Explanation:

A box with a weight of 650 N is sitting on the ground .

Dimensions of bottom surface of block

length = 0.7 m breadth = .5 m

To Find:

What is the pressure exerted by the box on the ground

Solution:

Pressure is defined as the External normal force acting on body per unit area.

Pressure is always normal to surface.

Pressure can be measured using barometers, manometers etc.

Pressure = \frac{Normal force}{Area}Pressure=

Area

Normalforce

S.I Unit of Pressure = \frac{N}{m^{2} }

m

2

N

or Pascal.

Pressure is a scalar quantity.

Normal force = 650 N

Area = .5 ×.7 =.35 m^{2}m

2

\begin{gathered}P = \frac{650}{.35} \\\\P = 1857.14 Pa\end{gathered}

P=

.35

650

P=1857.14Pa

Pressure exerted by the block on the ground is equal to 1857.14 Pa.