A boxcontains cards bearing number 6to7. If on card is drawn at random from the box find probability .
a) a one digit number .
b) a number divisible by 5.
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Answer:
total cards =2(6,7)
Step-by-step explanation:
a) both 6 and 7 are one digit numbers therefore the probability of getting and one digit number is is 1 that is it is a sure event
b) number divisible by 5 is not present in the sample space as both 6 and 7 not multiples of 5 and have not the the factor as 5 Inder prime factorization that the probability of of getting a number divisible by 5 is zero that is it is impossible event.
hope you understand please Marcus brainliest thank you
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