Question

a boy 1.6 metre tall is 20 metre away from a tower and observes the angle of elevation of the top of the tower to be 45° 60° find the height of the tower in each case​

Answer 1

Answer:

hope it helps

Step-by-step explanation:

Let AC be tower 

DE=1.6m as BC =1.6 m 

DC =20 m as BE = 20 m

so, in triangle ABE

tan 60= AB/BE

√3 =AB/20

AB =20√3m

so,the height of the tower = AC =AB+BC =20√3+1.6

                                                               =20×1.732+1.6 =34.64 +1.6

                                                                =36.24 m

same steps 45'