Question

A boy and a man carry a uniform pole of length 8 m and of mass 60 kg by supporting it on their shoulders. they are located at the ends of the pole. where should a load of 90 kg be suspended from boy's end so that boy carries only one - third of the total load ?

Answer 1

.............................

Answer 2

Answer:

6.22

Explanation:

the mass of pole acts from its center c.

let the load be placed at a distance x from the boy's end.

if N1,N2 are the normal reactions on man and body respectively...then

N1=2/3(60+90)g=100g

N2=1/3(60+90)g=50g

N1=100 g

N2=50 g

taking turning effects about boys end B ,we have

N1×8-60g×4-90g×X=0

X=6.22m