Math, asked by siddhantsinghbeast17, 4 months ago

A boy attempts x+y sums. Out of which y-2z are wrong attempts. Find the number of correct attempts.​

Answers

Answered by Anonymous
2

Answer:

(x+y)−(y−2z)=x+y−y+2z=x+2 z. Answered By. toppr. How satisfied are you with the answer? This will help us to improve ...

Top answer

Wrong sums = (x + y) - (y - 2z) = x + y - y + 2z = x + 2z More

Answered by bhuyanshazida
0

Total sums attempted = x+y

Wrong attempts= y-2z

Therefore no of correct attempts=

x+y

(-) y-2z

= x+0+2z

=x+2z

So , number of correct attempts= x+2z

Mark my answer as brainliest

Similar questions