A boy attempts x+y sums. Out of which y-2z are wrong attempts. Find the number of correct attempts.
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(x+y)−(y−2z)=x+y−y+2z=x+2 z. Answered By. toppr. How satisfied are you with the answer? This will help us to improve ...
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Wrong sums = (x + y) - (y - 2z) = x + y - y + 2z = x + 2z More
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Total sums attempted = x+y
Wrong attempts= y-2z
Therefore no of correct attempts=
x+y
(-) y-2z
= x+0+2z
=x+2z
So , number of correct attempts= x+2z
Mark my answer as brainliest
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