Question

A boy buys 9 apples for rs 9.60 and sells them at 11 for rs 12. Find his gain percent or loss percent.

Answer 1

Answer:

Step-by-step explanation:

Cost price of 9 apples = Rs.9.60

∴ cost price of 1 apple = Rs:9.60/9

Selling price of 11 apple = Rs. 12

∴ selling price of 1 apple = Rs:12/11

Gain = 12/11-9.60/9=108-105.60/99=RS:2.40/99

= GAIN PERCENTAGE: gain/cost price*100

=2.40/99/9.60/9*100=25/11=2{ 3/11} percent

Answer 2

$\frak{\pink{Given:}} \begin{cases} \sf{\orange{Cost ~ Price ~of~ 9 ~apples = Rs. 9.60}} \\ \\ \sf{\orange{ Cost~ price ~of~ 1 ~apple = Rs. \dfrac{9.60}{9}}} \\ \\ \sf{\orange{ Selling~ price~ of~ 11 ~apple = Rs. 12 }}\\ \\ \sf {\orange{Selling~ price~ of~ 1 ~apple = Rs. \dfrac{ 12}{11}}} \end{cases}$

By using the formula,

Gain = selling price – cost price

$\implies \sf \dfrac{12}{11} - \dfrac{9.60}{9}$

$\implies \sf \dfrac{ (108-105.60)}{99}$

$\implies \sf{\orange{= Rs \dfrac{2.40}{99}}}$

By using the formula,

$\boxed{\orange{\sf {Gain \% = \bigg(\dfrac{gain}{cost\; price}\bigg) \times 100}}}$

$\implies \sf \Bigg[\dfrac{\Big(\dfrac{2.40}{99}\Big)}{\Big(\dfrac{9.60}{9}\Big)}\Bigg] \times 100$

$\implies \sf \dfrac{25}{11}$

$\implies\orange{ \sf 2\dfrac{3}{11}\%}$

Therefore, the loss percent is ${ \sf 2\dfrac{3}{11}\%}$.

__________________

Hope it elps! :p