Question

A boy can throw a stone up to a maximum height of 10m. the maximum horizontal distance that the boy can throw the same stone upto will be?
1) 20m
2) 20√2 m
3} 10m
4) 10√2 m ​

Answer 1

Answer:

For vertically projected up body maximum height (H) is given as

H=

(2g)

u

2

.......(1)

For the same bocy with same initial velocity the horizontal distance traveled when thrown at an angle(θ) is given as

R=

g

u

2

...........(2)

Compare equations 1 and 2

R=2H

R=2×10

R=20 m

Answer 2

it has given that, A boy can throw a stone up to a maximum height of 10m.

To find : The maximum horizontal distance that the boy can throw the same stone upto will be...

solution : maximum height, h = 10m

let initial speed of stone thrown by the boy = u

at maximum height, v = 0

so using, v² = u² + 2as

here v = 0, a = -g = -10 m/s² and s = h = 10

now, u² = 2 × 10 × 10 = 200

⇒u = 10√2 m/s

time taken, t = √{2h/g} = √{2 × 10/10} = √2

now maximum horizontal distance, R = ut

= 10√2 × √2 = 20 m

Therefore the maximum horizontal distance that the boy can throw the same stone upto will be 20m