A boy can throw a stone upto a maximum height of 10 m. The maximum horizontal distance that the boy can throw the same stone up to will be
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10
Answer:
20m
Explanation:
Given vertical height = 10m. if we took it as max vertical height
then, u2/2g = 10m => u2/g = 20
As horizontal projectile range = u2sin2∂/g
So, range is maximum when ∂=45 degrees
Hence, maximum horizontal range is u2/2g = 20,m
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