Question

A boy can throw a stone upto a maximum height of 10m . The maximum horizontal distance that the bot can throw the same stone upto will be [AIEEE 2012] ​

Answer 1

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A boy can throw a stone upto a maximum height of 10m . The maximum horizontal distance that the bot can throw the same stone upto will be

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Maximum vertical height = u2/2g = 10 m

Horizontal range of a projectile = u2 sin2θ/g

Range is maximum when θ = 45°

Maximum horizontal range = u2/g

Hence, maximum horizontal distance = 20 m

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Answer 2

Explanation:- maximum speed with which the boy can throw stone is

u = √2gh

= √2*10*10

=10√2m/s

Range is maximum when projectile is through at an angle of 45° ,thus

Rᵐᵃˣ = u²/g

=( 10√2)²/10

= 20 m Answer