A boy contains 1coins and 2coins whose total value is 70.if the number of 1 coins is five times that of 2coins find the number of coins of each type
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ur question is wrong.
sAmjhe
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Answer:
let the no. of 2coins be x
then,the no. of 1coins be 5x
total value =70
the value of 2coins =x=2×x=2x
then,the value of 1coins=5x=5x×1=5x
a/q 2x+5x=70
= 7x=70
= x=70÷7
=x=10 ans.
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