Question

. A boy contains 3 blue, 4 black and 8 white balls.
ains 3 blue, 4 black and 8 white balls. If a ball is picked at random without
looking into the bag, find the probability of obtaining:
White ball (ii) a blue ball (iii) other than black ball (iv) blue or black ball​

Answer 1

Answer:

A) white ball=8/15

B)blue ball=3/15=1/5

C)other than black ball=11/15

D)blue or black ball=3/15+4/15=7/15

Mark it brainliest plz

Answer 2

Answer:

Blue=B,black=R,white =W.

S={B1,B2,B3,R1,R2,R3,R4,W1,W2,W3,W4,W5,W6,W7,W8}

n(S)=15

(i)E={W1,W2,W3,W4,W5,W6,W7,W8}

n(E)=8

p(E)=n(E)/n(S) =8/15

(ii)A={B1,B2,B3}

n(A)=3

p(A)=n(A)/p(A) =3/15 =1/5

(iii)C={B1,B2,B3,W1,W2,W3,W4,W5,W6,W7,W8}

n(C)=11

p(C)=n(C)/n(S) =11/15

(iv)D={B1,B2,B3,R1,R2,R3,R4}

n(D)=7

p(D)=n(D)/n(S) =7/15