Question

a boy contains 7 yellow balls 4 green balls 9 orange balls find the probability of a.)orangeballs b.)green balls c.) yellow balls?? full sum?​

Answer 1

total outcome = 20

$p(orange \: ball) = \frac{9}{20}$

$p(green \: balls) = \frac{4}{20} = \frac{1}{5}$

$p(yellow \: balls) = \frac{7}{20}$