Question

A boy covers a distance of 260 m in
20 s and another distance of 300 m
in 20 s. The average speed of the boy
is :
​

Answer 1

Answer:

14 m/s

Explanation:

Average Speed = Total distance / Total time

=> 260 m + 300 m / 20s + 20s

=> 560 m / 40 s

=> 14 m/s

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Answer 2

Given :-

Distance covered by the boy first = 260 m

Distance covered by the boy second = 300 m

Time taken by the boy first = 20 sec

Time taken by the boy second = 20 sec

To Find :-

The average speed of the boy.

Analysis :-

Firstly find the total distance covered by the boy by adding both the distances.

Then add both the time taken and find the total time.

In order to find the average speed, divide the total distance by the total time taken by the boy.

Solution :-

Total distance,

Total distance = d₁ + d₂

Substituting their values,

⇒ 260 + 300

⇒ 560 m

Total time,

Total time = t₁ + t₂

Substituting their values,

⇒ 20 + 20

⇒ 40 sec

Using the formula,

$\underline{\boxed{\sf Average \ speed=\dfrac{Total \ distance \ covered}{Total \ time \ taken} }}$

Given that

Distance (d) = 560 m

Time (t) = 40 sec

Substituting their values,

⇒ s = 560/40

⇒ s = 56/4

⇒ s = 14 m/s

Therefore, the average speed of the boy is 14 m/s.